Skip to main content

Theoretical BER vs SNR for BPSK


Theoretical Bit Error Rate (BER) vs Signal-to-Noise Ratio (SNR) for BPSK in AWGN Channel

Let’s simplify the explanation for the theoretical Bit Error Rate (BER) versus Signal-to-Noise Ratio (SNR) for Binary Phase Shift Keying (BPSK) in an Additive White Gaussian Noise (AWGN) channel.


Key Points

Constellation diagrams of BASK, BFSK, and BPSK
Fig. 1: Constellation Diagrams of BASK, BFSK, and BPSK [↗]

BPSK Modulation

Transmits one of two signals: +√Eb or −√Eb, where Eb is the energy per bit. These signals represent binary 0 and 1.


AWGN Channel

The channel adds Gaussian noise with zero mean and variance N₀/2 (where N₀ is the noise power spectral density).


Receiver Decision

The receiver decides if the received signal is closer to +√Eb (for bit 0) or −√Eb (for bit 1).


Bit Error Rate (BER)

The probability of error (BER) for BPSK is given by the Q-function, which measures the tail probability of the normal distribution — i.e., the probability that a Gaussian random variable exceeds a certain value.


Understanding the Q-function

The Q-function, Q(x), gives the probability that a standard normal (Gaussian) random variable exceeds x. In this context, it gives the probability that noise pushes the received signal across the wrong decision boundary, resulting in a bit error.

For BPSK, bits ‘0’ and ‘1’ map to +1 and −1, respectively. The probability of error is the probability that noise exceeds a threshold, depending on the signal’s distance from zero.

Calculate the Probability of Error using Q-function

For a Gaussian noise with mean = 0 and variance = N₀/2, the probability of error is:

Pb = Q(1/σ)

where σ = √(N₀/2)

So, Pb = Q(√(2/N₀))

Since SNR = Eb/N₀, we get:

Pb = Q(√(2 × SNR)) or equivalently Q(√(2Eb/N₀)).


Formula for BER

BER = Q(√(2Eb/N₀))

Here, Eb/N₀ is the energy per bit to noise power spectral density ratio, also known as the bit SNR.


Simplified Steps

  1. Calculate the SNR: γb = Eb/N₀
  2. Find the Q-function value: BER = Q(√(2γb))

Intuition

For High SNR (γb is large):

The argument of the Q-function √(2γb) becomes large, Q(x) is small ⇒ fewer errors. Result: BER is low.

For Low SNR (γb is small):

The argument of the Q-function √(2γb) is small, Q(x) is larger ⇒ more errors. Result: BER is higher.


Approximation for High SNR

For large SNR, the BER can be approximated using the complementary error function (erfc):

Q(x) ≈ ½ erfc(x/√2)

Thus, BER ≈ ½ erfc(√γb)

So, the final formula for BPSK in AWGN is:

BER = Q(√(2Eb/N₀))

Higher SNR ⇒ lower BER ⇒ better performance and fewer errors.


MATLAB Code: Theoretical BER vs SNR for BPSK

% The code is written by SalimWireless.Com 

clc;
clear;
close all;

snrdb = 0:1:10;
snrlin = 10.^(snrdb./10);
tber = 0.5 .* erfc(sqrt(snrlin));
semilogy(snrdb, tber, '-bh')
grid on
title('BPSK with AWGN');
xlabel('Signal to noise ratio');
ylabel('Bit error rate');

Output

Theoretical BER vs SNR for BPSK in AWGN
Figure: Theoretical BER vs SNR for BPSK

BER vs SNR Simulation





Contact Us

Name

Email *

Message *

Popular Posts

Constellation Diagram of FSK in Detail

📘 Overview 🧮 Simulator for constellation diagram of FSK 🧮 Theory 🧮 MATLAB Code 📚 Further Reading 📚 BER vs SNR from Constellation   Binary bits '0' and '1' can be mapped to 'j' and '1' to '1', respectively, for Baseband Binary Frequency Shift Keying (BFSK) . Signals are in phase here. These bits can be mapped into baseband representation for a number of uses, including power spectral density (PSD) calculations. For passband BFSK transmission, we can modulate signal 'j' with a lower carrier frequency and signal '1' with a higher carrier frequency while transmitting over a wireless channel. Let's assume we are transmitting carrier signal fc1 for the transmission of binary bit '1' and carrier signal fc2 for the transmission of binary bit '0'. Simulator for 2-FSK Constellation Diagram Simulator for 2-FSK Constellation Diagram ...

UGC NET Electronic Science Previous Year Question Papers with Solutions

Home / Engineering & Other Exams / UGC NET 2026 PYQ ⬇️ Download Papers and Solutions 📋 Exam Pattern 💡 Preparation Tips ❓ FAQs 📊 Exam Highlights: Electronic Science (88) Feature Details Junior Research Fellowship (JRF) ₹37,000 + HRA per month Eligibility M.Sc/M.Tech in Electronics (55%) Validity of Certificate JRF (3 Years) | Lectureship (Lifetime) 📥 Download UGC NET Electronics PDFs Complete collection of previous year question papers, answer keys and explanations for Subject Code 88. Start Downloading 📂 View All Question Papers June 2025 - Question Paper Download PDF June 2025 - Solved Paper + Explanation ...

FM Bandwidth and FM Band Explained

FM radio uses the frequency band from 88 MHz to 108 MHz , which is a 20 MHz-wide spectrum . This is the range of carrier frequencies available to stations. 108 MHz − 88 MHz = 20 MHz However, a single FM station occupies only about 200 kHz . This is the bandwidth of the modulated FM signal. 1. Why One FM Station Needs ~200 kHz FM uses frequency modulation . The bandwidth depends on how far the carrier swings. Carson's Rule gives the approximate FM bandwidth: B = 2 ( Δf + f m ) ...

What is Frequency Resolution?

  Formula for Frequency Resolution (in general) The frequency resolution is the smallest frequency difference between two adjacent frequency points in your sampling range. It is determined by the total frequency range and the number of frequency samples  N . The formula for the frequency resolution (or step size)  Δf  is: Δf = (f max  - f min ) / (N - 1) Where: f min  is the minimum frequency in the range (in this case, -50 Hz). f max  is the maximum frequency in the range (in this case, 50 Hz). N  is the number of frequency points / frequency bins. Using the Given Values: From the function: f min  = -50 Hz f max  = 50 Hz N  = 1000 The frequency resolution is: Δf = (50 - (-50)) / (1000 - 1) = 100 / 999 ≈ 0.1001 Hz   Understanding Frequency Resolution in Signal Processing Alternative Formula Using Time Duration Another common way to define frequency resolution, especially in time-domain signal processing, is: Δf = 1 / T W...

Ph.D. admissions in IITs without a GATE score

PhD Admission in IITs With Low CGPA approximately 6.5 – 7.0 / 10 No valid GATE score Willing to strengthen research proposal, contact faculty, apply to multiple institutes Expanded List of IITs: Eligibility & Links IIT Eligibility & Notes PhD Info Link IIT Gandhinagar Minimum: 60% marks or 6.0 CGPA (General) or 55%/5.5 (SC/ST/PD) in qualifying degree.  GATE/NET may be waived in certain cases; but short‑listing criteria likely higher. iitgn.ac.in/admissions/phd IIT Kharagpur Minimum eligibility: 60% marks or 6.5 CGPA in qualifying exam for many branches.  However brochure notes “for test & interview this minimum must be met and higher cut‑offs may apply”. iitkgp.ac.in/phd_brochure.pdf IIT Bhubaneswar Minimum: Engineering Schools – M.Tech/ME with minimum 60% marks or 6.5 CGPA....

BER performance of QPSK with BPSK, 4-QAM, 16-QAM, 64-QAM, 256-QAM, etc (MATLAB + Simulator)

📘 Overview 📚 QPSK vs BPSK and QAM: A Comparison of Modulation Schemes in Wireless Communication 📚 Real-World Example 🧮 MATLAB Code 📚 Further Reading   QPSK provides twice the data rate compared to BPSK. However, the bit error rate (BER) is approximately the same as BPSK at low SNR values when gray coding is used. On the other hand, QPSK exhibits similar spectral efficiency to 4-QAM and 16-QAM under low SNR conditions. In very noisy channels, QPSK can sometimes achieve better spectral efficiency than 4-QAM or 16-QAM. In practical wireless communication scenarios, QPSK is commonly used along with QAM techniques, especially where adaptive modulation is applied. Modulation Bits/Symbol Points in Constellation Usage Notes BPSK 1 2 Very robust, used in weak signals QPSK 2 4 Balanced speed & reliability 4-QAM ...

Coherence Bandwidth and Coherence Time (with MATLAB + Simulator)

🧮 Coherence Bandwidth 🧮 Coherence Time 🧮 MATLAB Code s 📚 Further Reading For Doppler Delay or Multi-path Delay Coherence time T coh ∝ 1 / v max (For slow fading, coherence time T coh is greater than the signaling interval.) Coherence bandwidth W coh ∝ 1 / Ï„ max (For frequency-flat fading, coherence bandwidth W coh is greater than the signaling bandwidth.) Where: T coh = coherence time W coh = coherence bandwidth v max = maximum Doppler frequency (or maximum Doppler shift) Ï„ max = maximum excess delay (maximum time delay spread) Notes: The notation v max −1 and Ï„ max −1 indicate inverse proportionality. Doppler spread refers to the range of frequency shifts caused by relative motion, determining T coh . Delay spread (or multipath delay spread) determines W coh . Frequency-flat fading occurs when W coh is greater than the signaling bandwidth. Coherence Bandwidth Coherence bandwidth is...