Skip to main content

BER vs SNR for M-ary QAM, M-ary PSK, QPSK, BPSK, ...(MATLAB Code + Simulator)


Bit Error Rate (BER) & SNR Guide

Analyze communication system performance with our interactive simulators and MATLAB tools.



What is Bit Error Rate (BER)?

The BER indicates how many corrupted bits are received compared to the total number of bits sent. It is the primary figure of merit for any digital communication link.

BER = (number of bits received in error) / (total number of transmitted bits)

What is Signal-to-Noise Ratio (SNR)?

SNR is the ratio of signal power to noise power, typically expressed in decibels (dB) to handle large variations in signal strength.

SNR (dB) = 10 * log10(Signal Power / Noise Power)

Example: An SNR of 3 dB means signal power is 2x stronger than noise.


Theoretical Error Probability of Digital Modulation

Key Concept: The performance of a modulation scheme is measured by how many errors occur for a given signal strength. We distinguish between Bit Error Rate (BER)—the probability of a single bit being wrong—and Symbol Error Rate (SER)—the probability of a group of bits (a symbol) being wrong.

1. Bit Error Rate (BER) Formulas

BER indicates the end-to-end performance of a data link. For higher-order modulation like QAM, we use approximations based on Gray Coding (where adjacent symbols differ by only one bit).

Binary Phase Shift Keying (BPSK)

The baseline for performance; very robust against noise.

\[ P_b = Q\left(\sqrt{\frac{2E_b}{N_0}}\right) \] Quadrature Phase Shift Keying (QPSK)

Carries 2 bits per symbol but maintains the same BER as BPSK.

\[ P_b = Q\left(\sqrt{\frac{2E_b}{N_0}}\right) \] M-ary PSK (e.g., 8-PSK) \[ P_b \approx \frac{2}{\log_2(M)} Q\left( \sqrt{\frac{2E_s}{N_0}} \sin\left(\frac{\pi}{M}\right) \right) \] Rectangular M-ary QAM (16, 64, 256-QAM)

As M increases, the distance between points decreases, making them more sensitive to noise.

16-QAM: \[ P_b \approx \frac{3}{4} Q\left( \sqrt{\frac{4}{5}\frac{E_b}{N_0}} \right) \]

64-QAM: \[ P_b \approx \frac{7}{12} Q\left( \sqrt{\frac{2}{7}\frac{E_b}{N_0}} \right) \]

256-QAM: \[ P_b \approx \frac{15}{32} Q\left( \sqrt{\frac{8}{85}\frac{E_b}{N_0}} \right) \]


2. Symbol Error Rate (SER) Formulas

SER is useful for designing the physical layer and hardware. One symbol error usually results in only one bit error if Gray Coding is used.

BPSK & QPSK

BPSK: \[ P_s = Q\left(\sqrt{\frac{2E_b}{N_0}}\right) \]

QPSK: \[ P_s \approx 2Q\left(\sqrt{\frac{2E_b}{N_0}}\right) \]

General M-QAM Symbol Error Rate

A symbol is "lost" if the noise pushes it outside its decision boundary.

16-QAM: \[ P_s \approx 3Q\left( \sqrt{\frac{4}{5}\frac{E_b}{N_0}} \right) \]

64-QAM: \[ P_s \approx \frac{7}{2} Q\left( \sqrt{\frac{2}{7}\frac{E_b}{N_0}} \right) \]


Summary of Parameters

  • \(E_b\): Energy required to send one bit.
  • \(E_s\): Energy required to send one symbol (\(E_s = E_b \cdot \log_2 M\)).
  • \(N_0\): Noise power density.
  • AWGN Channel: These formulas assume a static environment with only Gaussian noise (no fading).
  • Gray Coding: A technique where adjacent constellation points differ by only one bit to minimize BER.

Interactive BER Calculator

Calculate theoretical BER for PSK and QAM systems instantly.

M-ary PSK

---

M-ary QAM

---

Performance Comparison

BER vs. SNR Graph
Download MATLAB BER Code →
Technique Bits/Symbol
BPSK1
QPSK2
8-PSK3
16-QAM4
64-QAM6

Modulation Scheme and Bandwidth Requirement

Modulation Bits/Symbol Bandwidth
BPSK 1 Rb
QPSK 2 Rb / 2
8-PSK 3 Rb / 3
16-QAM 4 Rb / 4

Read more about Modulation Scheme & Bandwidth Requirement



Try Interactive Online Simulators


BER Requirements by Application

Technology Typical Modulation Target BER
5G Mobile Data 256-QAM 10-4 to 10-6
Satellite Comms (Deep Space) BPSK / QPSK 10-3 (Pre-FEC)
Fiber Optic Networks Coherent QAM 10-12
Submarine Cables 8-QAM / 16-QAM 10-15

Quick Knowledge Check

If you double the signal power (increase by 3dB), what happens to the SNR?


QPSK vs. 4-QAM: Why They Should Have Same BER?

In digital communications, QPSK and 4-QAM exhibit identical Bit Error Rate (BER) performance. Although they are categorized differently, they share the same constellation geometry and power efficiency.

📚 Also Read About

Frequently Asked Questions

What is a good BER for wireless communication?

For voice transmission, a BER of 10^-3 is often acceptable. For high-speed data services, a BER of 10^-6 or lower is typically required.

How does SNR affect BER?

As SNR increases, the signal becomes clearer relative to the noise, resulting in a significantly lower Bit Error Rate.

Contact Us

Name

Email *

Message *

Popular Posts

OFDM Symbols and Subcarriers Explained

This article explains how OFDM (Orthogonal Frequency Division Multiplexing) symbols and subcarriers work. It covers modulation, mapping symbols to subcarriers, subcarrier frequency spacing, IFFT synthesis, cyclic prefix, and transmission. Step 1: Modulation First, modulate the input bitstream. For example, with 16-QAM , each group of 4 bits maps to one QAM symbol. Suppose we generate a sequence of QAM symbols: s0, s1, s2, s3, s4, s5, …, s63 Step 2: Mapping Symbols to Subcarriers Assume N sub = 8 subcarriers. Each OFDM symbol in the frequency domain contains 8 QAM symbols (one per subcarrier): Mapping (example) OFDM symbol 1 → s0, s1, s2, s3, s4, s5, s6, s7 OFDM symbol 2 → s8, s9, s10, s11, s12, s13, s14, s15 … OFDM sym...

UGC NET Electronic Science Previous Year Question Papers with Solutions

Home / Engineering & Other Exams / UGC NET 2026 PYQ ⬇️ Download Papers and Solutions 📋 Exam Pattern 💡 Preparation Tips ❓ FAQs 📊 Exam Highlights: Electronic Science (88) Feature Details Junior Research Fellowship (JRF) ₹37,000 + HRA per month Eligibility M.Sc/M.Tech in Electronics (55%) Validity of Certificate JRF (3 Years) | Lectureship (Lifetime) 📥 Download UGC NET Electronics PDFs Complete collection of previous year question papers, answer keys and explanations for Subject Code 88. Start Downloading 📂 View All Question Papers June 2025 - Question Paper Download PDF June 2025 - Solved Paper + Explanation ...

Choke Input Filter Explained

  Choke Input Filter Choke Input Filter A well-designed choke input filter is a type of power supply filter used to smooth the output of a rectifier (like in DC power supplies). It uses an inductor (choke) as the first component right after the rectifier, followed by a capacitor. Basic Structure Rectifier → Choke (L) → Capacitor (C) → Load What Makes It Well-Designed? Critical Inductance is satisfied: The choke must have enough inductance to keep current flowing continuously. This minimum value is called critical inductance. Low ripple output: A good design significantly reduces AC ripple in the DC output. The choke resists sudden changes in current. Proper load current: Works best when the load current is above a certain minimum level. Too light a load results in poor filter...

Intel 8086 Transistor Count: Architecture, Specifications, and Comparison with Other Microprocessors

Intel 8086 Transistor Count: Architecture, Specifications, and Comparison with Other Microprocessors Intel 8086 Transistor Count: Complete Guide with Architecture and Processor Comparison The Intel 8086 microprocessor is one of the most important processors in computer history. Released in 1978 , it introduced the x86 architecture that still influences modern CPUs. One of the most frequently asked questions in computer architecture and microprocessor courses is: How many transistors are present in the Intel 8086? The commonly accepted answer is approximately 29,000 transistors . However, reverse-engineering studies have shown that the actual number of physical transistors is closer to 19,618 , while Intel's published figure includes programmable transistor locations used in ROM and PLA structures. Intel 8086 Transistor Count Metric Value Published transistor count ~29,000 Physical transistor count ~19,618 Release year 1978 Word ...

FM Bandwidth and FM Band Explained

FM radio uses the frequency band from 88 MHz to 108 MHz , which is a 20 MHz-wide spectrum . This is the range of carrier frequencies available to stations. 108 MHz − 88 MHz = 20 MHz However, a single FM station occupies only about 200 kHz . This is the bandwidth of the modulated FM signal. 1. Why One FM Station Needs ~200 kHz FM uses frequency modulation . The bandwidth depends on how far the carrier swings. Carson's Rule gives the approximate FM bandwidth: B = 2 ( Δf + f m ) ...

Overmodulation & Distortion in AM

Overmodulation in AM and How It Causes Distortion 1. AM Signal Equation s(t) = A c [1 + μ m(t)] cos(2Ï€ f c t) A c = carrier amplitude m(t) = normalized modulating signal (|m(t)| ≤ 1) μ = modulation index 2. Modulation Index μ = A m / A c - Normal AM: 0 < μ ≤ 1 → no distortion - Overmodulation: μ > 1 → distortion occurs 3. Envelope and Overmodulation A(t) = A c [1 + μ m(t)] - For undistorted AM: 1 + μ m(t) ≥ 0 at all times - If μ > 1: 1 + μ m(t) < 0 at negative peaks → carrier flips Example: Let m(t) = cos(2Ï€ f m t), A c = 1 V, μ = 1.2 Minimum envelope: A min = A c [1 - 1.2] = -0.2 V Negative amplitude → envelope crosses zero → 180° phase flip 4. Mathematical Consequence -A c cos(θ) = A c cos(θ + Ï€) This phase reversal is what causes distortion in the demodulated signal. 5. Instantaneous AM Signal s...