Skip to main content

Channel Impulse Response (CIR) (with MATLAB + Simulator)


What is the Channel Impulse Response (CIR)?

The Channel Impulse Response (CIR) is a concept primarily used in the field of telecommunications and signal processing. It provides information about how a communication channel responds to an impulse signal.

It describes the behavior of a communication channel in response to an impulse signal. In signal processing, an impulse signal has zero amplitude at all other times and amplitude at time 0 for the signal. Using a Dirac Delta function, we can approximate this.

Dirac Delta Function
Fig: Dirac Delta Function

The result of this calculation is that all frequencies are responded to equally by δ(t). This is crucial since we never know which frequencies a system will affect when examining an unidentified one. Since it can test the system for all frequencies, δ(t) becomes the perfect option for determining how a system will react.


Channel Impulse Response (CIR) and Multi-path

If we send a signal in the typical wireless communication medium, that signal will arrive at the receiver as MPCs or multi-paths [Read more]. They arrive at the recipient at different times, and are linear in nature, delayed variants of the same signal.

The Doppler effect is detected when either the transmitter or receiver, or both, are moving. The receiving frequency increases as the mobile station approaches the base station. When the mobile station moves away, the receiving frequency decreases.

y(t) = Σ x (t - Ï„) h (t, Ï„) …(iii)

A radio channel’s time‑variant impulse response, where the channel impulse response or channel gain varies with time, is described as h (t). When a signal is sent from the transmitter, it arrives at the receiver with a time delay of x (t ‑ Ï„). They are duplicates of the same signal that arrive at the receiver via numerous reflecting or refractive pathways. They’re also linear because they’re scalar multiples of one another.

Channel impulse response illustration

The above equation (ii) represents the convolution of the transmitted signal with the channel impulse response. Equation (ii) can be rewritten as y(t) = (h * x)(t), where '*' denotes convolution.


How does the channel impulse response affect the signal?

Real‑world wireless communication is often modelled as a Linear Time‑Invariant (LTI) system, where it is assumed that the channel gain remains constant during the transmission of each symbol. However, channel estimation is frequently performed to track time‑varying channel conditions. In this model, the original message bits or symbols are affected by the wireless channel, which can be represented as the convolution of the transmitted signal with the channel’s impulse response. This impulse response accounts for the different path gains caused by multipath propagation. As a result, the receiver does not receive the original signal directly. These multipath components can interfere constructively or destructively, significantly altering the received signal.

Original message signal
Fig: Original Message Signal
Channel Impulse Response due to multipath or Rayleigh fading
Fig: Channel Impulse Response (due to Multi‑path or Rayleigh Fading)
Received signal after demodulation with fading and noise
Fig: Received Signal after demodulation at the receiver side, which is affected by both Rayleigh fading and AWGN noise

Online Channel Impulse Response Simulator


Summary

In a Linear Time‑Invariant (LTI) system, the output y(t) is given by the convolution of the input signal x(t) with the system’s impulse response h(t):

y(t) = x(t) ∗ h(t)

‘∗’ denotes the convolution operation in the time domain.

When the input signal is an impulse δ(t), the output of the LTI system is the impulse response h(t). This is because the convolution of an impulse with any function returns that function:

δ(t) ∗ h(t) = h(t)

However, if the input impulse and the received impulse response are not correlated as expected, several factors could be contributing to this discrepancy.


How to calculate bit error rate (BER) from Channel Impulse Response

To calculate BER versus SNR from a channel impulse response (CIR), you first need to obtain the CIR, which characterizes the effect of the communication channel. Generate a transmitted signal, convolve it with the CIR, and add white Gaussian noise (AWGN) to simulate the received signal. The Signal‑to‑Noise Ratio (SNR) is calculated as the ratio of the signal power to the noise power, typically expressed in decibels (dB). Demodulate the received signal and compare it with the original transmitted signal to compute the Bit Error Rate (BER).


MATLAB code for channel impulse response estimation using FFT‑based channel estimation method

Screenshot of MATLAB channel estimation code
(Get the MATLAB Code)

Deep Dive:

The channel impulse response is calculated using a simple trick. We begin by sending a pilot signal from the transmitter. The data is then retrieved, and the channel Impulse response is calculated. The pilot signal (or bits) are pre‑determined. To receive regular updates on channel Impulse Response, we repeat the method in short intervals. The channel Impulse Response is also affected by the environment, such as indoor, outdoor, industrial, residential, etc.

As previously stated, channel impulse response varies depending on the surroundings. For example, channel impulse responses or generated multi‑paths are higher in an indoor environment than in an outdoor environment. On the other hand, while comparing different indoor environments, we find that the industrial indoor environment has a higher number of multipath than any other. Because many reflections and refraction on metallic surfaces of heavy equipment, machinery, and other objects generate MPCs in that environment. Compared to MPCs generated outdoors, MPCs formed indoors are closer in time. MPCs are developed outside because of structures, foliage, and other factors. However, compared to indoors, the distance between the transmitter and receiver is greater. As a result, multipath takes longer to reach the receiver than inside.

We generally see clusters in the channel impulse response at higher frequencies (CIR). When MPCs arrive at the receiver and are near in time, they form a cluster. Similarly, there could be several clusters. Let’s say we want to send an impulse signal from the transmitter. The signal then travels 100 multipath to reach the receiver. The first 40 MPCs arrive at the receiver in 50 milliseconds, followed by the next 60 MPCs in a 20‑millisecond interval, all arriving within 70 milliseconds. The period of the first cluster is 50 milliseconds, and the time duration of the second cluster is 70 milliseconds. And while the time gap between the two clusters is 20 milliseconds, the total duration of the channel impulse response is (50 + 20 + 70) milliseconds.



Further Reading

  1. Online Channel Impulse Response Simulator
  2. What is convolution (full convolution)
  3. Convolution in LTI Wireless Communication Systems
  4. Equalizer to reduce Multi‑path Effects using MATLAB
  5. Channel Impulse Response in the Typical Wireless Communication
  6. MATLAB Code for BER vs SNR from Channel Impulse Response
  7. Convolution in LTI Wireless Communication Systems
  8. Gaussian Random Variable (RV) and its PDF
  9. Doppler Shift
  10. Fading – Slow & Fast and Large & Small Scale Fading
  11. Equalizer – Fundamentals of Channel Estimation
  12. Impact of Rayleigh Fading and AWGN on Digital Communication Systems
  13. Channel Matrix Gain

Contact Us

Name

Email *

Message *

Popular Posts

Constellation Diagram of FSK in Detail

📘 Overview 🧮 Simulator for constellation diagram of FSK 🧮 Theory 🧮 MATLAB Code 📚 Further Reading 📚 BER vs SNR from Constellation   Binary bits '0' and '1' can be mapped to 'j' and '1' to '1', respectively, for Baseband Binary Frequency Shift Keying (BFSK) . Signals are in phase here. These bits can be mapped into baseband representation for a number of uses, including power spectral density (PSD) calculations. For passband BFSK transmission, we can modulate signal 'j' with a lower carrier frequency and signal '1' with a higher carrier frequency while transmitting over a wireless channel. Let's assume we are transmitting carrier signal fc1 for the transmission of binary bit '1' and carrier signal fc2 for the transmission of binary bit '0'. Simulator for 2-FSK Constellation Diagram Simulator for 2-FSK Constellation Diagram ...

UGC NET Electronic Science Previous Year Question Papers with Solutions

Home / Engineering & Other Exams / UGC NET 2026 PYQ ⬇️ Download Papers and Solutions 📋 Exam Pattern 💡 Preparation Tips ❓ FAQs 📊 Exam Highlights: Electronic Science (88) Feature Details Junior Research Fellowship (JRF) ₹37,000 + HRA per month Eligibility M.Sc/M.Tech in Electronics (55%) Validity of Certificate JRF (3 Years) | Lectureship (Lifetime) 📥 Download UGC NET Electronics PDFs Complete collection of previous year question papers, answer keys and explanations for Subject Code 88. Start Downloading 📂 View All Question Papers June 2025 - Question Paper Download PDF June 2025 - Solved Paper + Explanation ...

DFTs-OFDM vs OFDM: Why DFT-Spread OFDM Reduces PAPR Effectively (with MATLAB Code)

Understanding PAPR in DFT-spread OFDM vs. Standard OFDM In modern wireless communications like 4G LTE and 5G NR, managing the Peak-to-Average Power Ratio (PAPR) is critical for hardware efficiency. While OFDM is the gold standard for high-speed data, its high PAPR poses significant challenges for mobile devices. This is where DFTs-OFDM (also known as SC-FDMA) comes in. DFT-spread OFDM (DFTs-OFDM) has lower Peak-to-Average Power Ratio (PAPR) because it "spreads" the data in the frequency domain before applying IFFT, making the time-domain signal behave more like a single-carrier signal rather than a multi-carrier one like OFDM. Deeper Explanation: Aspect OFDM DFTs-OFDM Signal Type Multi-carrier Single-carrier-like Process IFFT of QAM directly QAM → DFT → IFFT PAPR Level High (due to many...

Simulation of ASK, FSK, and PSK using MATLAB Simulink (with Online Simulator)

📘 Overview 🧮 How to use MATLAB Simulink 🧮 Simulation of ASK using MATLAB Simulink 🧮 Simulation of FSK using MATLAB Simulink 🧮 Simulation of PSK using MATLAB Simulink 🧮 Simulator for ASK, FSK, and PSK 🧮 Digital Signal Processing Simulator 📚 Further Reading 📚 BER vs SNR Simulation 📚 Constellation Simulation ASK, FSK & PSK HomePage MATLAB Simulation Simulation of Amplitude Shift Keying (ASK) using MATLAB Simulink In Simulink, we pick different components/elements from MATLAB Simulink Library. Then we connect the components and perform a particular operation. Result A sine wave source, a pulse generator, a product block, a mux, and a scope are shown in the diagram above. The pulse generator generates the '1' and '0' bit sequences. Sine wave sources produce a specific amplitude and frequency. The scope displays the modulated signal as well as the...

Online Simulator for ASK, FSK, and PSK

Interactive Digital Signal Processing (DSP) Tutorial and Simulator for ASK, FSK, and BPSK modulation techniques. Try our new Digital Signal Processing Simulator!   •   Interactive ASK, FSK, and BPSK tools updated for 2025. Start Now Digital Modulation Visualizer: ASK, FSK, & BPSK Simulator Learn and visualize binary modulation techniques (ASK, FSK, BPSK) in real-time with adjustable carrier and sampling parameters. Perfect for DSP students and engineers. 📡 ASK Simulator 📶 FSK Simulator 🎚️ BPSK Simulator 📚 More Topics ASK Modulator FSK Modulator BPSK Modulator More Topics 1. ASK (Amplitude Shift Keying) Simulat...

FM Bandwidth and FM Band Explained

FM radio uses the frequency band from 88 MHz to 108 MHz , which is a 20 MHz-wide spectrum . This is the range of carrier frequencies available to stations. 108 MHz − 88 MHz = 20 MHz However, a single FM station occupies only about 200 kHz . This is the bandwidth of the modulated FM signal. 1. Why One FM Station Needs ~200 kHz FM uses frequency modulation . The bandwidth depends on how far the carrier swings. Carson's Rule gives the approximate FM bandwidth: B = 2 ( Δf + f m ) ...

What is Frequency Resolution?

  Formula for Frequency Resolution (in general) The frequency resolution is the smallest frequency difference between two adjacent frequency points in your sampling range. It is determined by the total frequency range and the number of frequency samples  N . The formula for the frequency resolution (or step size)  Δf  is: Δf = (f max  - f min ) / (N - 1) Where: f min  is the minimum frequency in the range (in this case, -50 Hz). f max  is the maximum frequency in the range (in this case, 50 Hz). N  is the number of frequency points / frequency bins. Using the Given Values: From the function: f min  = -50 Hz f max  = 50 Hz N  = 1000 The frequency resolution is: Δf = (50 - (-50)) / (1000 - 1) = 100 / 999 ≈ 0.1001 Hz   Understanding Frequency Resolution in Signal Processing Alternative Formula Using Time Duration Another common way to define frequency resolution, especially in time-domain signal processing, is: Δf = 1 / T W...