PSK vs Minimum Shift Keying Modulation (MSK) Number of Bits: Carrier Frequency (Hz): Baud Rate (Hz): Show Frequency Spectrum Theory: Understanding MSK Modulation What is MSK? Minimum Shift Keying (MSK) is a specialized form of Continuous Phase Frequency Shift Keying (CPFSK). In standard FSK, switching between frequencies can cause "glitches" or phase jumps. MSK ensures the phase ...

GMSK Virtual Lab Gaussian Minimum Shift Keying Modulation (GMSK) Note: Use input fields for bits, frequency, BT, and baud rate. In GMSK, the filtered NRZ signal is integrated to produce a continuous phase signal. Number of Bits: Carrier Frequency (Hz): Time-Bandwidth (BT): Baud Rate (Hz): GMSK Demodulation Click 'Demodulate' to extrac...

Minimum Shift Keying Modulation (MSK) Number of Bits: Carrier Frequency (Hz): Baud Rate (Hz): Show Frequency Spectrum Theory: Understanding MSK Modulation What is MSK? Minimum Shift Keying (MSK) is a specialized form of Continuous Phase Frequency Shift Keying (CPFSK). In standard FSK, switching between frequencies can cause "glitches" or phase jumps. MSK ensures the phase transit...

  54) Which of the following are the major steps which are taken to troubleshoot a microcomputer system? Assume all ICs are in the socket. Identify the symptoms and make a careful visual and tactical inspection. Check the power supply. Switch OFF and ON the system. Check the control signals such as RD , WR , ALE, RDY and RESET Choose the correct answer from the options given below: 1. A and C only [Option ID = 3125] 2. A, B and D only [Option ID = 3126] 3. A, B and C only [Option ID = 3127] 4. C and D only [Option ID = 3128] Answer: 1 Previous yr Question papers with Full Explanations → Electronics and Communiaction Study Materials →

53) Which of the following is/are NOT processor control instructions? STC CLC JNZ NOP CMC Choose the correct answer from the options given below: 1. A, B and E only [Option ID = 3121] 2. C and D only [Option ID = 3122] 3. C and B only [Option ID = 3123] 4. D and E only [Option ID = 3124] Answer: A Previous yr Question papers with Full Explanations → Electronics and Communiaction Study Materials →

52) For a JK Flip-flop: When J = 0, K = 1, Q n+1 = 0 When J = 1, K = 1, Q n+1 = 1 When J = 1, K = 1, Q n+1 = Q- n When J = 1, K = 0, Q n+1 = 1 When J = 1, K = 0, Q n+1 = 0 Choose the correct answer from the options given below: 1. A, C and D only [Option ID = 3117] 2. B and D only [Option ID = 3118] 3. C and E only [Option ID = 3119] 4. A, C and E only [Option ID = 3120] Answer: 1 Solution Statement A: When J = 0, K = 1,  Q n + 1 = 0 Q n + 1 ​ = 0 Evaluation: Correct. This is the Reset condition. Statement B: When J = 1, K = 1,  Q n + 1 = 1 Q n + 1 ​ = 1 Evaluation: Incorrect. When both inputs are 1, the output toggles ( Q ˉ n Q ˉ ​ n ​ ), it isn't fixed at 1. Statement C: When J = 1, K = 1,  Q n + 1 = Q ˉ n Q n + 1 ​ = Q ˉ ​ n ​ Evaluation: Correct. This is the standard Toggle con...