Radar Receiver MDS Simulator Radar MDS Simulator Bandwidth (MHz): Noise Figure (dB): Temperature (K): Calculate

Force Summing Device Force Summing Device Definition A force summing device is a mechanical element used to combine multiple input forces into a single resultant force. It is widely used in systems where several forces act simultaneously and need to be analyzed or converted into motion. Basic Concept When two or more forces act on a system, the resultant force is given by: F resultant = F₁ + F₂ + F₃ + ... This combined force produces displacement, motion, or deformation. Working Principle Multiple forces are applied to the system. The device mechanically sums these forces. The resultant force acts on a component (spring, mass, etc.). An output such as displacement or motion is produced. Examples Weighing Scale: Combines weight forces to produce displacement. Spring-Mass Sys...

Two-Transistor Model Two-Transistor Model (BJT / Thyristor) 1. Basic Idea The two-transistor model represents a device (especially a thyristor/SCR ) using: One PNP transistor (T₁) One NPN transistor (T₂) The transistors are connected so that the collector of one feeds the base of the other, creating positive feedback . 2. Structure T₁ (PNP) T₂ (NPN) ----------- ----------- Collector of T₁ → Base of T₂ Collector of T₂ → Base of T₁ 3. Current Relations Let: α₁ = current gain of T₁ α₂ = current gain of T₂ Total current through device: I = I input / (1 - (α₁ + α₂)) 4. Turn-ON Condition α₁ + α₂ → 1 When this condition is met: Denominator → 0 Current rises rapidly Device switches ON (latches) 5. Working Principle OFF State: α₁...

The transfer function of the system shown in the following figure is:   A. G₁G₂ + 1 B. G₁ + G₂ + 1 C. G₁G₂ + G₁ + 1 D. G₁G₂ + G₂ + 1 Step 1: Identify the signals Input = R(s) After block G₁ = G₁R(s) Step 2: First summing junction Inputs: - Output of G₁ = G₁R(s) - Direct input = R(s) Therefore, X(s) = G₁R(s) + R(s) = (G₁ + 1)R(s) Step 3: Pass through G₂ Output = G₂ × X(s) = G₂(G₁ + 1)R(s) Step 4: Second summing junction Inputs: - Output of G₂ = G₂(G₁ + 1)R(s) - Direct input = R(s) Therefore, C(s) = G₂(G₁ + 1)R(s) + R(s) Step 5: Transfer function C(s)/R(s) = G₂(G₁ + 1) + 1 Expanding: = G₁G₂ + G₂ + 1 Final Answer: Option D → G₁G₂ + G₂ + 1

Advanced Modulation Power Simulator Advanced Modulation Power Simulator Modulation Type: AM FM PM Carrier Amplitude (Ac): Load Resistance (R): Modulation Index (m): Enter values to see results...

Power of a PM Signal Power of a PM (Phase Modulated) Signal 1. PM Signal Form A phase modulated signal is written as: s(t) = A c cos(ω c t + k p m(t)) Where: A c = carrier amplitude k p = phase sensitivity m(t) = message signal 2. Total Power of PM Signal P PM = A c 2 / (2R) This is the same as carrier power. 3. Key Concept Amplitude remains constant Only phase changes Power depends on amplitude, so it remains constant 4. Power Distribution Total power is constant Distributed among: Carrier Infinite sidebands (theoretical) As modulation increases: Carrier power decreases Sideband power increases Total power remains unchanged 5. Key Observations ...

Power of an FM Signal Power of an FM (Frequency Modulated) Signal 1. FM Signal Form An FM signal is written as: s(t) = A c cos(ω c t + β sin(ω m t)) Where: A c = carrier amplitude β = modulation index ω c , ω m = carrier and message frequencies 2. Total Power of FM Signal P FM = A c 2 / (2R) This is the same as carrier power. 3. Important Concept FM does not change amplitude Only frequency varies Power depends only on amplitude, which is constant 4. Power Distribution in FM Total power is constant Distributed among: Carrier Infinite sidebands (theoretical) As β increases: Carrier power decreases Sideband power increases Total power remains constant ...

Power of an AM Signal Power of an AM (Amplitude Modulated) Signal 1. Standard AM Signal Form An AM signal is written as: s(t) = A c [1 + m cos(ω m t)] cos(ω c t) Where: A c = carrier amplitude m = modulation index (0 to 1) ω c , ω m = carrier and message frequencies 2. Total Power in AM Signal The total transmitted power is: P total = P c (1 + m²/2) Where: P c = A c ² / (2R) R = load resistance 3. Sideband Power Total sideband power: P SB = P c × (m² / 2) Each sideband has: P USB = P LSB = (P c × m²) / 4 4. Key Observations Carrier consumes most power Efficiency depends on modulation index (m) Maximum efficiency at m = 1 5. Efficiency of AM η = m² / (2 + m²) Maximum efficiency = 33.33%...