76) Arrange the following in ascending order of their conductivity. A. Silicon dioxide B. Intrinsic Silicon C. Extrinsic Silicon D. Aluminium Choose the correct answer from the options given below: 1. A, B, C, D [Option ID = 3133] 2. B, C, D, A [Option ID = 3134] 3. C, D, A, B [Option ID = 3135] 4. D, A, B, C [Option ID = 3136] Answer: A Previous yr Question papers with Full Explanations → Electronics and Communiaction Study Materials →

75) Match List I with List II List I (Performance Characteristic) List II (Definition) A. Correction I. Nearness of indicated value to the true value of the quantity being measured B. Precision II. Opposite of error C. Accuracy III. Closeness with which the same value of input quantity is measured under different conditions D. Reproducibility IV. Degree of refinement with which a measured value is stated Choose the correct answer from the options given below: 1. A-II, B-IV, C-I, D-III [Option ID = 312...

74) Match List I with List II List I (f(t)) List II (F(s)) A. e -at i. s / (s 2 + ω 2 ) B. te -at ii. ω / (s 2 + ω 2 ) C. sin ωt iii. 1 / (s + a) 2 D. cos ωt iv. 1 / (s + a) Choose the correct answer from the options given below: 1. A-I, B-II, C-III, D-IV [Option ID = 3125] 2. A-III, B-II, C-I, D-IV [Option ID = 3126] 3. A-IV, B-III, C-I, D-II [Option ID = 3127] 4. A-IV, B-III, C-II, D-I [Option ID = 3128] Answer: D Previous yr Question papers ...

Universal Wireless Access Lab (TDMA, FDMA, SDMA) Interactive exploration of TDMA, FDMA, and SDMA modulation logic. TDMA (Time) FDMA (Frequency) SDMA (Space) TDMA: Time Division Multiple Access Users share the entire frequency band , but only for a specific time slot . The Mathematics: Frame Duration: $T_f = N \times (T_s + T_g)$ Throughput per User: $R_u = \frac{R_{total}}{N} \times \frac{T_s}{T_s + T_g}$ N = Number of Users T_s = Slot Duration | T_g = Guard Time (prevents overlap) Guard Time Intensi...

Why Frequency Hopping is the Secret Weapon of CDMA | Wireless Security Explained Telecommunications & Engineering Why Frequency Hopping is the Secret Weapon of CDMA: The Math Behind Bulletproof Wireless Ever wonder why your Bluetooth headphones don't cut out when the microwave starts, or how military radios stay "invisible" to enemies? The answer lies in Frequency Hopping CDMA (FH-CDMA) . #CDMA #WirelessSecurity #EngineeringMath The "Invisible" Signal: What is FH-CDMA? In standard radio, you transmit on one fixed frequency. In Frequency Hopping Spread Spectrum (FHSS) , the carrier jumps—or "hops"—between many frequencies at incredible speeds. When combined with Code Division Multiple Access (CDMA) , it creates a system where only a receiver with the "secret code" can follow the conversation. Think of it like this: Imagine trying to follow a conversation where the speakers telepo...

73) Match List I with List II List I List II A. FDMA I. Frequency Hopping B. TDMA II. Guard Band C. CDMA III. Onboard Switching D. SDMA IV. Guard Time Choose the correct answer from the options given below: A - II, B - IV, C - I, D - III [Option ID = 3121] A - IV, B - II, C - III, D - I [Option ID = 3122] A - I, B - III, C - II, D - IV [Option ID = 3123] A - III, B - I, C - II, D - IV [Option ID = 3124] Answer: A Previous yr Question papers with Full Explanations → Electronics and Communiaction Study Materials → ...

72) Match List I with List II List I (US New Military Bands for Microwave) List II (Frequency range in GHz) A. H band I. 6.000-8.000 GHz B. J band II. 10.000-20.000 GHz C. G band III. 4.000-6.000 GHz D. E band IV. 2.000-3.000 GHz Choose the correct answer from the options given below: A - I, B - II, C - III, D - IV [Option ID = 3117] A - IV, B - III, C - II, D - I [Option ID = 3118] A - II, B - I, C - III, D - IV [Option ID = 3119] A - III, B - II, C - IV, D - I [Option ID = 3120] Answer: A Previous yr Question papers with Full Explanations → ...

71) Match List I with List II List I (Assembly code) List II (Content of register A after the code) A. MOV A, #37H CPL A I. 02H B. MOV A, #37H ANL A, #8AH II. F7H C. MOV A, #37H ORL A, #8AH III. FBH D. MOV A, #37H XRL A, #8AH IV. C8H Choose the correct answer from the options given below: A - IV, B - I, C - III, D - II [Option ID = 3113] A - I, B - II, C - III, D - IV [Option ID = 3114] A - IV, B - I, C - II, D - III [Option ID = 3115] A - III, B - I, C - IV, D - II [Option ID = 3116] Answer: A Solution To solve this assembly code problem, we convert the hexadeci...