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Impulse Response h[n] of an ARMA System Step-by-Step Solution 1. Start with the Transfer Function: Given: H(z) = (1 + 0.3z⁻¹) / (1 - 0.75z⁻¹ + 0.5z⁻²) This is an ARMA(2,1) system where: MA (numerator) coefficients: [1, 0.3] AR (denominator) coefficients: [1, -0.75, 0.5] 2. Find the Impulse Response h[n]: We want the inverse Z-transform of H(z). Instead of doing partial fraction decomposition, we use the system's difference equation. 3. Recursive Computation Using the Difference Equation: From the system equation: y[n] + 0.75y[n−1] − 0.5y[n−2] = x[n] + 0.3x[n−1] Assume x[n] = δ[n] (unit impulse): x[0] = 1 , others are 0. Then y[n] = h[n] 4. Compute h[n] values: n = 0: y[0] + 0 = 1 → h[0] = 1 n = 1: y[1] + 0.75*1 = 0.3 → h[1] = -0.45 n = 2: y[2] - 0.3375 - 0.5 = 0 → h[2] = 0.8375 n = 3: y[3] + 0.628125 + 0.225 = 0 → h[3] = -0.853125 5. Table of Fi...